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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
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Question 1 of 5
1. Question
Global population was around 1.6 billion in 1990—today it is around 7.2 billion and growing. Recent estimates on population growth predict a global population of 9.6 billion in 2050 and 10.9 billion in 2100. Unlike Europe and North America, where only three to four per cent of population is engaged in agriculture, around 47 per cent of India’s population is dependent upon agriculture. Even if India continues to do well in the service sector and the manufacturing sector picks up, it is expected that around 2030 when India overtakes China as the world’s most populous country, nearly 42 per cent of India’s population will still be predominantly dependent on agriculture.
Which of the following is the mostlogical and rational inference that can be made from the above passage?
Correct
Ans. B. The focus of the passage is on explaining the high dependency of Indian economy on agriculture even when the other sectors of the economy start doing well. Hence B
Incorrect
Ans. B. The focus of the passage is on explaining the high dependency of Indian economy on agriculture even when the other sectors of the economy start doing well. Hence B

Question 2 of 5
2. Question
It is known that the HCF of two numbers, x and y is 1. Which of the following statement is definitely false?
Correct
Solution: C
Let’s analyse all the options:
Option (a): It is possible that HCF is 1 when one number is even and other is odd. E.g. Let 6 and 5 are two numbers which are even and odd respectively and the HCF of these two numbers is 1. Hence, this statement may be true.
Option (b): It is possible that HCF is 1 when both numbers are odd. E.g. Let 7 and 9 are the two numbers which are odd and the HCF of these two numbers is 1. Hence, this statement may be true too.
Option (d): It is possible that HCF is 1 when at least one of two numbers, i.e. x and y, is prime. E.g. Let 5 and 12 are two numbers and HCF of these two numbers is 1. Hence, this may also be true.
Option (c): When both the numbers are even, 2 is definitely a common factor. Hence, this statement is definitely false.
Hence, option (c) is the correct.
Incorrect
Solution: C
Let’s analyse all the options:
Option (a): It is possible that HCF is 1 when one number is even and other is odd. E.g. Let 6 and 5 are two numbers which are even and odd respectively and the HCF of these two numbers is 1. Hence, this statement may be true.
Option (b): It is possible that HCF is 1 when both numbers are odd. E.g. Let 7 and 9 are the two numbers which are odd and the HCF of these two numbers is 1. Hence, this statement may be true too.
Option (d): It is possible that HCF is 1 when at least one of two numbers, i.e. x and y, is prime. E.g. Let 5 and 12 are two numbers and HCF of these two numbers is 1. Hence, this may also be true.
Option (c): When both the numbers are even, 2 is definitely a common factor. Hence, this statement is definitely false.
Hence, option (c) is the correct.

Question 3 of 5
3. Question
The average weight of a class of 20 students is 45 kgs. A new student, whose weight is 40 kgs, replaces an old student of this class. Hence, the average weight of the whole class decreases by 1 kg. The weight of the replaced
student is:Correct
Solution: C
Initially the total weight of class = 20 x 45 = 900 kgs
Now, the total weight when a student has been replaced = 20 x 44 = 880 kgs.
It means that the weight of the new student is 20 kgs less than the replaced student. Hence, the weight of the replaced student = 40 + 20 = 60 kgs.Hence, option (c) is correct.
Incorrect
Solution: C
Initially the total weight of class = 20 x 45 = 900 kgs
Now, the total weight when a student has been replaced = 20 x 44 = 880 kgs.
It means that the weight of the new student is 20 kgs less than the replaced student. Hence, the weight of the replaced student = 40 + 20 = 60 kgs.Hence, option (c) is correct.

Question 4 of 5
4. Question
A shopkeeper sells 100 pens and in the process gains the selling price of 40 pens. What is the profit percentage?
Correct
Solution: B
Let the selling price of one pen be = S
Thus, selling price of 100 pens is 100S
It is given that; profit is equal to selling price of 40 pens (40 S)
Thus, cost price of 100 pens is (100 S 40 S= 60 S)
Thus, on cost price of 60 S profit is 40 S
Thus, profit percent = (40S/60S) X 100= 66.67%Hence, option (b) is correct.
Incorrect
Solution: B
Let the selling price of one pen be = S
Thus, selling price of 100 pens is 100S
It is given that; profit is equal to selling price of 40 pens (40 S)
Thus, cost price of 100 pens is (100 S 40 S= 60 S)
Thus, on cost price of 60 S profit is 40 S
Thus, profit percent = (40S/60S) X 100= 66.67%Hence, option (b) is correct.

Question 5 of 5
5. Question
Pointing to a man in a photograph a woman says, “He is the father of my only daughterinlaw’s fatherinlaw”. How is the man related to the woman?
Correct
Solution: D
Woman’s daughterinlaw’s fatherinlaw implies woman’s husband.
Again, the father of the woman’s husband implies woman’s fatherinlaw.
Hence, the man is woman’s fatherinlaw
Hence, option(d) is correct.
Incorrect
Solution: D
Woman’s daughterinlaw’s fatherinlaw implies woman’s husband.
Again, the father of the woman’s husband implies woman’s fatherinlaw.
Hence, the man is woman’s fatherinlaw
Hence, option(d) is correct.