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Considering the alarming importance of CSAT in UPSC CSE Prelims exam and with enormous requests we received recently, InsightsIAS has started Daily CSAT Test to ensure students practice CSAT Questions on a daily basis. Regular Practice would help one overcome the fear of CSAT too.
We are naming this initiative as Insta– DART – Daily Aptitude and Reasoning Test. We hope you will be able to use DART to hit bull’s eye in CSAT paper and comfortably score 100+ even in the most difficult question paper that UPSC can give you in CSP2021. Your peace of mind after every step of this exam is very important for us.
Looking forward to your enthusiastic participation (both in sending us questions and solving them on daily basis on this portal).
Wish you all the best ! 🙂
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Question 1 of 5
1. Question
Each of two women and three men is to occupy one chair out of eight chairs, each of which numbered from 1 to 8. First, women are to occupy any two chairs from those numbered 1 to 4; and then the three men would occupy any, three chairs out of the remaining six chairs. What is the maximum number of different ways in which this can be done?
Correct
Answer : C
Explanation: 2 Women can occupy 2 chairs out of the first four chairs in 4P2 ways. 3 men can be arranged in the remaining 6 chairs in 6P3 ways. Hence, total no. of ways = 4P2 × 6P3 = 1440
Incorrect
Answer : C
Explanation: 2 Women can occupy 2 chairs out of the first four chairs in 4P2 ways. 3 men can be arranged in the remaining 6 chairs in 6P3 ways. Hence, total no. of ways = 4P2 × 6P3 = 1440

Question 2 of 5
2. Question
Pipe A can fill a tank in 10 min and pipe B can empty it in 15 min. If both the pipes are opened in an empty tank, the time taken to make it full is
Correct
Answer : C
Answer Justification : Part filled by pipe A in 1 min = 1/10 Part empty by pipe B in 1 min = 1/15 Total tank filled in minutes = 1/10 – 1/15 = 1/30 Hence, the tank will be filled in 30 min
Incorrect
Answer : C
Answer Justification : Part filled by pipe A in 1 min = 1/10 Part empty by pipe B in 1 min = 1/15 Total tank filled in minutes = 1/10 – 1/15 = 1/30 Hence, the tank will be filled in 30 min

Question 3 of 5
3. Question
In a chess competition involving some boys and girls of a school, every student had to play exactly one game with every other student. It was found that in 45 games both the players were girls and in 190 games both were boys. The number of games in which one player was a boy and the other was a girl is
Correct
Answer : A
Explanation: Let number of girls = x The number of boys = y 45 games in which both the players were girls
xC2 = 45 x! / 2!(x2)! = x(x1) = 90 Therefore, x = 10. 190 games, where both the players were boys. yC2 = 190 = y(y – 1) = 380 y = 20 Hence the total number of games in which one player was a boy and the other was a girl = 10 × 20 = 200
Incorrect
Answer : A
Explanation: Let number of girls = x The number of boys = y 45 games in which both the players were girls
xC2 = 45 x! / 2!(x2)! = x(x1) = 90 Therefore, x = 10. 190 games, where both the players were boys. yC2 = 190 = y(y – 1) = 380 y = 20 Hence the total number of games in which one player was a boy and the other was a girl = 10 × 20 = 200

Question 4 of 5
4. Question
In a group of persons travelling in a bus, 6 persons can speak Tamil, 15 can speak Hindi and 6 can speak Gujarati. In that group none can speak any other language. If 2 persons in the group can speak two languages only and one person can speak all the three languages, then how many persons are there in the group?
Correct
Answer : C
Explanation: Let a = Speaks one language Let b = Speaks two language Let c = Speaks three language then a + 2b + 3c = 6 +15 +6 a + 4 + 3 = 27 a = 20 Total number of persons in the group = 20 + 2 + 1 = 23.
Incorrect
Answer : C
Explanation: Let a = Speaks one language Let b = Speaks two language Let c = Speaks three language then a + 2b + 3c = 6 +15 +6 a + 4 + 3 = 27 a = 20 Total number of persons in the group = 20 + 2 + 1 = 23.

Question 5 of 5
5. Question
‘X’ is twice as old as ‘Y’ 3 years ago, when ‘X’ was as old as ‘Y’ today. If the difference between their ages as present is 3 years, how old is ‘X’ at present?
Correct
Answer : C
Explanation: Let present age of X = x years .
Present age of Y = (x – 3) years
3 years ago, age of X = (x – 3) years Age of Y = (x – 6) years
According to the question, x – 3 = 2(x – 6) x – 3 = 2x – 12 12 – 3 = 2x – x
x = 9 years
Incorrect
Answer : C
Explanation: Let present age of X = x years .
Present age of Y = (x – 3) years
3 years ago, age of X = (x – 3) years Age of Y = (x – 6) years
According to the question, x – 3 = 2(x – 6) x – 3 = 2x – 12 12 – 3 = 2x – x
x = 9 years